$10g$ of hydrogen and $64g$ of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be:

The correct option is B $4moles$
$\underset{1mol}{H_2}+\underset{0.5mol}{\frac{1}{2}{O}_2}\to \underset{1mol}{H_{2}O}$

No. of moles of $H_2=\frac{10}{2}=5,$

No.of moles of $O_2=\frac{64}{32}=2mol$

As 1 mol of$O_2$ gives 2 moles of $H_{2}O$

Then 2 moles of $O_2$ gives 4 moles of $H_{2}O$.

Because oxygen is the limiting regent, hence 4 moles of $H_{2}O$ formed.