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Osmotic Pressure

24. 200ml of ...

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24. 200ml of an aqueous solution of a protein contains it's 1.26g.The osmotic pressure of this solution at 300K is found to be 2.57×10-3bar. The molar mass of protein will be (R=0.083Lbar mol-1 K-1) 1. 31011 g mol-1 2. 61038 g mol-1 3. 51022 g mol-1 4. 122044 g mol-1

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200 m L

of an aqueous solution of a protein contains

1.26 g

of protein. The osmotic pressure of this solution at

300 K

2.57 \times 10^{- 3} b a r

. The molar mass of protein will be:

[R = 0.083 L bar mol

^{- 1}

^{- 1}

Q. 200 mL of an aqueous solution of a protein contains its 1.26 g. The Osmotic pressure of this solution at 300 K is found to be

2.57 \times 10^{- 3} b a r

.
The molar mass of protein will be (

R = 0.083 L b a r m o l^{- 1} K^{- 1}

Q. 200 mL of an aqueous solution of a protein contains its 1.26 g. The Osmotic pressure of this solution at 300 K is found to be

2.57 \times 10^{- 3} b a r

. The molar mass of protein will be (

R = 0.083 L b a r m o l^{- 1} K^{- 1}

):
(AIPMT 2011 MAINS )

Q. 0.2 L of aqueous solution of a protein contains 1.26 g of the protein. The osmotic pressure of such a solution at 300 K is found to be

2.57 \times 10^{- 3}

bar. Calculate the molar mass of the protein.

(R = 0.083 L b a r m o l^{- 1} K^{- 1})

200 mL

of an aqueous solution of a protein contains its

1.26 g

. The osmotic pressure of this solution at

300 K

2.52 \times 10^{- 3}

bar. The molar mass of protein will be

(R = 0.08 {L bar mol}^{- 1} K^{- 1})

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