$26cc$ of $C{O}_2$ are passed over red hot coke. The volume of $CO$ evolved is:
$C_{\left(s\right)}+C{O}_{2\left(g\right)}\to 2C{O}_{\left(s\right)}$

The correct option is D $Noneofthese$

Let us consider the problem.

Let us consider

$C{O}_2+C=2CO$

Therefore,

$22.4litreC{O}_{2}gives2\times 22.4litre$

$1litre----\frac{\left(2\times 22400\right)}{22400}$

$26ccC{O}_{2}givesCO=\frac{\left(2\times 22400\times 26\right)}{22400}=52ccCO$