Dalton's Law of Partial Pressures
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- The initial mixture taken should be an equimolar mixture of A and B
- The first vapours formed will have more moles of A as compared to moles of B
- PA=1000 mm of Hg
- The vapour pressure above the condenstate will be 920 mm of Hg at same temparature
What is the difference between vapor pressure and partial pressure?
- O2 and CO2
- N2 and O2
- Cl2 and O2
- NH3 and HCl
Equal masses of methane and oxygen are mixed in an empty container at 25 degrees centigrade. The fraction of the total pressure exerted by Oxygen is:
Options1)1/3
2)1/2
3)2/3
4)1/3*273/298
Answer is option1
At 300K, ozone is fifty percent dissociated. The standard free energy change at this temperature and 1 atm pressure is (-)
[Given: \ln1.35=0.3 and R=8.3JK−1mol−1]
temperature at which the flask will burst is _____∘C. [Nearest integer]
(Given: R=8.3 J K–1 mol–1, Atomic masses of C and H are 12u and 1u, respectively.) (Assume that
propane behaves as an ideal gas.)
the vapour pressure of two liquids A and B in their pure states are in ratio 1:2. A binary solution of A and B has A and B in mole proportion 1:2. The mole fraction of A in vapour phase of the solution will be ??
is the answer 0.33 or 0.2( because as the molefraction of A in vapour phase is used should we not use daltons law of partial pressure??)
A gaseous mixture of an equal mass of and is stored over water. if the total pressure is then the partial pressure of dry gas is ?(aqueous tension )
- PO2=19.75 bar, PNe=5.25 bar
- PO2=12.75 bar, PNe=12.25 bar
- PNe=19.75 bar, PO2=5.25 bar
- PNe=12.75 bar, PO2=12.25 bar
The pressure of a 1:4 mixture of dihydrogen and dioxygen enclosed in a vessel is one atmosphere. What would be the partial pressure of dioxygen?
(a) 0.8×105 atm (b) 0.008 Nm−2 (c) 8×104 Nm−2 (d) 0.25 atm
A mixture of dihydrogen and dioxygen at one bar pressure contains 20% by weight of dihydrogen. Calculate the partial pressure of dihydrogen.
Two solids dissociated as follows
The total pressure when both the solids dissociate simultaneously is:
- p(O2)=0.785 p(N2)
- p(O2)=8.75 p(N2)
- p(O2)=11.4 p(N2)
- p(O2)=0.875 p(N2)
- 15.45
- 14.45
- 17.45
- 16.45
A and B are ideal gases. The molecular weights of A and B are in the ratio of 1 : 4 . The pressure of a gas mixture containing equal weights of A and B is P atm. What is the partial pressure (in atm) of B in the mixture?
P/5
P/2
P/2.5
3P/4
- Raoult's law is obeyed for entire concentration range and temperatures
- ΔHmix=0
- ΔVmix=0
- ΔSmix=0
- 0.0375 M
- 0.028 M
- 0.0562 M
- 0.0187 M
- Both assertion and reason are true and reason is the correct explanation of assertion
- Both assertion and reason are true but reason is not the correct explanation of assertion
- Assertion is true but reason is false
- Both assertion and reason are false
- 0.487
- 0.352
- 0.892
- 0.665
The gas having the highest partial pressure in the atmosphere is –
PCl5(g)⇌PCl3(g)+Cl2(g)
PCl5 gas at a certain pressure is introduced in the container at 27 oC. However, the total pressure at equilibrium at 207 oC was found to be double the initial value. The % dissociation of PCl5 at 207 oC is:
A gaseous mixture of three gases A, B and C has a pressure of 10atm. The total number of moles of all gases is 10. The partial pressure of A and B are 3 and 1 atm respectively. If C has a molecular weight of 2, then find the weight of C in grams present in the mixture.
6
3
12
8
Dalton’s law of partial pressure is not applicable to a mixture of