Nernst Equation
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Write the Nernst equation and emf of the following cells at 298 K:
(i) Mg(s)|Mg2+(0.001M)||Cu2+(0.001M)|Cu(s)
(ii) Fe(s)|Fe2+(0.001M)||H+(1M)|H2(g)(1 bar)|Pt(s)
(iii) Sn(s)|Sn2+(0.050 M)||H+(0.020 M)|H2(g)(1 bar)|Pt(s)
(iv) Pt(s)|Br2(l)|Br−(0.010M)||H+(0.030M)|H2(g)(1bar|Pt(s))
E∘(Mg2+Mg)=−2.37V;E∘(Cu2+Cu)=+0.34V;E∘(Fe2+Fe)=−0.44V;E∘(Sn2+Sn)=−0.14V;E∘(1Br2Br−)=+1.08V,
Calcium hydroxide reacts with ammonium chloride to give ammonia, according to the following equation:
If of ammonium chloride is used, calculate:
(a) The mass of calcium chloride formed
(b) The volume, at STP of liberated.
(Atomic mass of Al=27 g mol–1)
- 2
- 3
- 1
- 4
The value of is at for the reaction . The value of for the following reaction is :
2Fe(s)+O2(g)+4H+(aq)→2Fe2+(aq)+2H2O(l) ; E∘=1.67 V
At [Fe2+]=10−3M, P(O2)=0.1 atm and pH = 3, the cell potential at 25 ∘C is
(given: 2.303RTF=0.0591)
- – 0.177 V
- 0.087 V
- 0.177 V
- 0.059 V
E° for F2 + 2e- -> 2F- is 2.8V, E° for 1÷2 F2 + e -> F- is
Ans : 2.8V
Please give detailed explanation as I won't be able to understand concise answers .
Pt(s)|H2(g, 1bar)|H+(aq, 1M)||M4+(aq), M2+(aq)|Pt(s)
Ecell=0.092V when[M2++(aq)][M4+(aq)]=10x
Given:E∘M4+/M2+=0.151V;2.303RTF=0.059V
The value of x is
- -2
- -1
- 1
- 2
The standard reduction electrode potential of four elements A, B, C and D are and respectively, the element with the highest reducing power is
A
B
C
D
The emf of the cell Ag|AgI|KI(0.05M)||AgNO3(0.05M)Ag is 0.788V. Calculate the solubility product of AgI.
- 1.10 x 10-16
25 X 10-13
- 6.6 x 10-19
- 8 x 10-11
- 0.2
- 0.1
- 0.4
- 0.5
- Electrolytic
- Electric
- Chemical
- Electrochemical
- Reduces by 0.03 V
- Increases by 1 V
- Reduces by 1 V
- Increases by 0.03 V
The concentration of potassium ions inside a biological cell is at least twenty times higher than the outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simple model for such a concentration cell involving a metal M is:
M(s)|M+ (aq;0.05 molar)||M+ (aq;1 molar)|M(s)
For the above electrolytic cell the magnitude of the cell potential |Ecell|=70 mV.
For the above cell
Ecell<0;Δ G>0
Ecell>0;Δ G<0
Ecell>0;Δ G0>0
Ecell>0;Δ G0<0
A+2B⇔C+2D the Initial rate −d[A]dt
at t = 0 was found to be 2.6×10−2Msec−1. What is the value of −d[B]dt at t = 0 in Msec−1?
- 2.6×10−2
- 0.1
- 5.2×10−2
- 6.5×10−3
Statements about heavy water are given below:
Heavy water is used in exchange reactions for the study of reaction mechanisms.
Heavy water is prepared by exhaustive electrolysis of water.
Heavy water has a higher boiling point than ordinary water.
The viscosity of is greater than .
Which of the above statements are correct?
A and B only
A and D only
A, B and C only
A and C only
- Acid rain
- Soil pollution
- Water pollution
- Global warming
- negatively charged
- positively charged
- neutral
- both negatively and positively charged.
1 mole of equimolar mixture of ferric oxalate and ferrous oxalate will require x mole of KMnO4 in acidic medium for complete oxidation, x is
0.9 mole
0.3 mole
1.8 mole
0.6 mole
Write Nernst equation for daniel cell at equilibrium condition and derive relationship between and equilibrium constant .
The single electrode potential of chloride electrode of [Cl‑] = 0.1 M is (EoCl2/Cl‑ is 1.36 V)
0.272 V
1.36 V
- 0.136 V
1.419 V
Cr(s)|Cr3+(aq)(0.1M)||Cu2+(aq)(0.5M)|Cu(s)
Find the value of Y
Pt (s) | Cl−(C1) | Cl2(g)(P1 atm) || Cl2(g)(P1 atm)| Cl−(C2)| Pt (s)
Identify in which of the following condition working of cell takes place:
- C1 > C2 and P1 = P2
- P2 > P1 and C1 = C2
- C1 < C2 and P1 = P2
- P2 < P1 and C1 = C2