Mean
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A lift can carry up to persons. At the ground floor whose weights are in increasing AP with an average weight of enter the lift. When the lift stops at floor whose weights are in an increasing AP enter the lift. The new average weight of people in the lift becomes . What is the weight of F?
The mean age of a combined group of men and women is 30 years. If the means of the age of men and women are respectively 32 and 27, then the percentage of women in the group is
- 60%
- 50%
- 30%
- 40%
- 100, 50
- 50, 100
- 75, 75
- 60, 90
The average weight of 35 students in a class is 40kg. If the weight of the teacher is also included, the average rises by 0.5 kg. The weight of the teacher is
40.5 kg
50 kg
58 kg
64 kg
- 189
- 21
- 31
- 48
Calculate the mean, median and standard deviation of the following distribution :
textClass−interval:31−3536−4041−4546−5051−5556−6061−6566−70Frequency:2381216523
The mean age of 50 persons was found to be 32 years. Later it was detected that the age 28 was wrongly noted as 35, the age 57 was wrongly noted as 30 and the age 60 was wrongly noted as 32. Then the correct mean age is
28
33
31
32.4
- −10.4
- 10.4
- 7.8
- 13
Let in a series of observations, half of them are equal to and the remaining half are equal to . Also by adding a constant in each of these observations, the mean and standard deviation of the new set become and , respectively. Then the value of is equal to:
425
The mean of the data set comprising of 16 observations is 16. If one of the observations valued 16 is deleted and three new observations valued 3, 4 and 5 added to the data, then the mean of the resultant data is
14.0
16.8
16.0
15.8
- 2+a+s
- 22+a
- 2s
- a+4
- 68
- 70
- 71
- 65
If the mean of 1, 2, 3, .........., n is 6n11, then n is
10
12
11
13
- 41 kg
- 58 kg
- 40.5 kg
- 50 kg
- 0
- 1
- 4
- 2
where a, b are two constants would be
- ¯¯¯x
- na¯¯¯x+nb
- a¯¯¯x
- a¯¯¯x+b
- 44.2
- 44.4
- 44.42
- 44.46
- the absolute value of difference between new mean and old mean is 15
- the absolute value of difference between new mean and old mean is 20
- the absolute value of difference between new mean and old mean is 0
- the position of new median will not change.
If the mean is 2.5, then the missing frequency x will be
Variable012345Frequencyx204040204
- 0
- 1
- 3
- 4
Find the harmonic mean of 1, 12, 13.
2
3
- 40 mph
- 48 mph
- 50 mph
- 55 mph
If the mean and variance of eight numbers and be and respectively then is equal to
- ¯¯¯x<¯¯¯x1
- ¯¯¯x>¯¯¯x2
- ¯¯¯x=¯¯¯x1+¯¯¯x22
- ¯¯¯x1<¯¯¯x<¯¯¯x2
- 25
- 35
- 49
- 45
The mean number of tails in three tosses of a fair coin is:
3
6
3/2
1/6
The following table shows the weight (in kg.) of persons:
Weight (in kg) | |||||||
Number of persons |
Find the mean, median and mode.
- 75
- 69
- 66
- 74