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Question

A 5.0 m mol dm3 aqueous soluion of KCl has a conductance of 0.55 mS when when measued in a cell of cell constant 1.3 cm1. The molar conductivity of this solution in mSm2 mol1 is
(Round off to the Nearest Integer)

(JEE MAIN 2021)

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Solution

Conductance=ConductivityCell Constant

Conductivity=0.55×103×1.3 S cm1

Molar conductivity=Conductivity(S cm1)×1000Molarity(mol/L)

Molar conductivity=0.55×103×1.3×10005×103

Molar conductivity=143 S cm2mol1

Molar conductivity=14.3 mS m2 mol1

Molar conductivity14 mS m2 mol1

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