A body executes simple harmonic motion. The potential energy (P.E.), the kinetic energy(K.E.) and total energy (T.E.) are measured as function of displacement x. Which of the following statement is true?

The correct option is A K.E. is maximum when x = 0
Energies of body of mass $m$ executing $SHM$ are given as-

Potential energy $P.E=\frac{1}{2}m{w}^2{x}^2$

Kinetic energy $K.E=\frac{1}{2}m{w}^2(A^2-x^2)$

Total energy $T.E=\frac{1}{2}m{w}^2{A}^2$

Conclusions:

P.E is minimum when $x=0$

Also, K.E is maximum where $x$ is minimum i.e at $x=0$

T.E is constant but never equals to zero.