A body falls from a height of 500 m. In how much time, will it strike the ground ? (Give the answer in seconds)

Q. At the equator a stationary (relative to the Earth) body falls down from the height $h=500m$ Assuming the air drag to be negligible, find how much off the vertical, and in what direction, the body will deviate when it hits the ground.

Q. A body falls freely from the top of a tower. It covers $36$% of the total height in the last second before striking the ground level. The height of the tower is

Q. When a body falls from rest its distance from the starting point varies as the square of the time it has been falling : if a body falls through $402\frac{1}{2}$ feet in $5$ seconds, how far does it fall in $10$ seconds? Also how far does it fall in the ${10}^{th}$ second?

Q. A body falls from a height of h = 3m. What is the total distance (in meters) it travels before it stops, if thebody falls from a height h, strikes the ground and rebounds to a height $e^{2}h$ , falls down $e^{2}h$ and then rebounds back to a height $e^{4}h$ and so on. The coefficient of restitution between body and ground is e = 0.55.

Q.

A body falls freely from rest. It covers as much distance in the last second of its motion as covered in the first three seconds. The body has fallen for a time;