A body is projected with kinetic energy E such that its range is maximum.Its potential energy at the maximum height is

4 K

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3 K

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2 K

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Zero

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Solution

The correct option is C 2 K
K.E = E = $\frac{1}{2} m u^{2}$ ; [ $∵ θ = 45^{0}$ ]
P.E = mgh = $m g (\frac{u^{2} s i n^{2} θ}{2 g})$
P.E = $(\frac{1}{2} m u^{2}) s i n^{2} 45 = E [\frac{1}{\sqrt{2}}]^{2}$
P.E = $\frac{E}{2}$

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