A body of mass $2 k g$ is dropped from a building of height $5 m$ . The maximum kinetic energy the body can attain is: (Take $g = 10 m s^{- 2}$ )

$50 J$

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$100 J$

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$150 J$

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$200 J$

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Solution

The correct option is B
$100 J$

Given:
Mass, $m = 2 k g$ ,
height, $h = 5 m$ ,
initial velocity, $u = 0 m s^{- 1}$ and
acceleration due to gravity $g = 10 m s^{- 2}$ .
Potential energy of the body, $P = m g h$
$\Rightarrow 2 \times 5 \times 10 = 100 J$ .
The potential energy becomes zero near ground and converts to kinetic energy of the body. Also, the body would attain the maximum kinetic energy just before it strikes the ground.
Hence, Kinetic energy = $100 J$ .

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A body of mass 2 kg is dropped from a building of height 5 m. The maximum kinetic energy the body can attain is: (Take g=10ms−2)

A body of mass $2 k g$ is dropped from a building of height $5 m$ . The maximum kinetic energy the body can attain is: (Take $g = 10 m s^{- 2}$ )