A body of mass $2kg$ is placed on a horizontal surface having kinetic friction $0\cdot 4$ and satic friction $0\cdot 5$. If the force applied on the body is $2\cdot 5N$, then the frictional force acting on the body will be

The correct option is C $2.5N$
The friction force is given by
$f=\mu N$
Kinetic friction ,
$f_k=0\cdot 4\times 2\times 10N=8N$
Static friction,
$f_s=0\cdot 5\times 2\times 10N=10N$
Since the applied force is less than force of friction, therefore the force of friction is eaqual to the applied force i.e. $2\cdot 5N$.
Final Answer:$\left(d\right)$