A body of mass $2$ kg is thrown vertically upwards with an initial velocity of $20$ m/s. What m: potential energy at the end of $2$ s? $g = 10 m / s^{2})$

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Solution

Given ,
Mass of body , $m = 2 k g$
Initial velocity $u = 20 m / s$

Height reached at $t = 2 s e c s h = u t - \frac{1}{2} g t^{2}$

$⟹ h = 20 \times 2 - \frac{1}{2} \times 10 \times 2^{2}$

$⟹ h = 20 m$

Potential energy , $P = m g h = 2 \times 10 \times 20 = 400 J$

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A body of mass 2 kg is thrown vertically upwards with an initial velocity of 20 m/s. What m: potential energy at the end of 2 s? g=10m/s2)

Given , Mass of body ,m=2 kg Initial velocity u=20m/sHeight reached at t=2secs h=ut−12gt2⟹h=20×2−12×10×22⟹h=20 mPotential energy , P=mgh=2×10×20=400 J

A body of mass $2$ kg is thrown vertically upwards with an initial velocity of $20$ m/s. What m: potential energy at the end of $2$ s? $g = 10 m / s^{2})$

Given ,
Mass of body , $m = 2 k g$
Initial velocity $u = 20 m / s$

Height reached at $t = 2 s e c s h = u t - \frac{1}{2} g t^{2}$

$⟹ h = 20 \times 2 - \frac{1}{2} \times 10 \times 2^{2}$

$⟹ h = 20 m$

Potential energy , $P = m g h = 2 \times 10 \times 20 = 400 J$