A body of mass $x$ kg is moving with a velocity of $100m{s}^{-1}$, if de Broglie wavelength is ${6.62\times 10}^{35}$ m. Hence, $x$ is:

$(h={6.62\times 10}^{-35}Js)$

The correct option is B $0.10kg$
Given that:

Planck's constant $\left(h\right)=6.62\times {10}^{-34}Js$

Mass of body $\left(m\right)=xkg$

velocity of body $\left(v\right)=100m/s$

de Broglie wavelength $\left(\lambda \right)=6.62\times {10}^{-35}m$

As we know that, de Broglie wavelength $\left(\lambda \right)$ is given by-

$\lambda =\frac{h}{mv}$

$6.62\times {10}^{-35}=\frac{6.62\times {10}^{-34}}{x\times 100}$

$\Rightarrow x=\frac{6.62\times {10}^{-34}}{6.62\times {10}^{-35}\times 100}=0.1kg$

Hence $x$ is $0.1kg$.

Hence the required answer is $0.1Kg$