A body subjected to three concurrent forces is found to be in equilibrium. The resultant of any two forces then will be

Q. Two forces each equal to $F/2$ act at right angle. Then-effect may be neutralized by a third force acting along their bisector in the opposite direction. What is the magnitude of that third force?

Q. $12$ coplanar non collinear forces (all of equal magnitude) maintain a body in equilibrium, then the angle between any two adjacent forces is:

Q. Three forces act on a body and the body stays at equilibrium. The direction of the two forces are shown in the figure. The direction of the third force to keep the body in equilibrium is (Given $F_1=F_2$)

Q. If a body is in equilibrium under a set of non collinear forces then the minimum number of forces has to be

Q. A $2\text{kg}$ object is subjected to three forces that give it an acceleration $\overrightarrow{a}=-\left(8\hat{i}\right){\text{m/s}}^2$. If two of the three forces are ${\overrightarrow{F}}_1=(30\hat{i}+16\hat{j})\text{N}$ and ${\overrightarrow{F}}_2=(-12\hat{i}+8\hat{j})\text{N}$, find the third force ($\text{in N}$).