A boy standing on a long railroad car throws a ball straight upwards. The car is moving on the horizontal road with an acceleration of $1 m / s^{2}$ and the projection speed in the vertical direction is $9.8 m / s$ . How far behind the boy will the ball fall on the car?

2 m

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5 m

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1 m

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7 m

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Solution

The correct option is A $2 m$
Let the initial velocity of car be ' $u$ '. time of flight,
$t = \frac{2 u_{y}}{g} = 2$
Where, $u_{y}$ = component of velocity in vertical direction
Distance travelled by car
$x_{c} = u \times 2 + \frac{1}{2} \times 1 \times 2^{2}$
$=$ $2 u + 2$
distance travelled by ball
$x_{b} = u \times 2$
$x_{c} - x_{b} = 2 u + 2 - 2 u$
$=$ $2 m$

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A boy standing on a long railroad car throws a ball straight upwards. The car is moving on the horizontal road with an acceleration of 1m/s2 and the projection speed in the vertical direction is 9.8m/s. How far behind the boy will the ball fall on the car?

The correct option is A 2mLet the initial velocity of car be 'u'. time of flight,t=2uyg=2Where, uy = component of velocity in vertical directionDistance travelled by carxc=u×2+12×1×22=2u+2distance travelled by ballxb=u×2xc−xb=2u+2−2u=2m

A boy standing on a long railroad car throws a ball straight upwards. The car is moving on the horizontal road with an acceleration of $1 m / s^{2}$ and the projection speed in the vertical direction is $9.8 m / s$ . How far behind the boy will the ball fall on the car?