A cake contains 1-5 kg sugar- 2-3 kg flour and 1-6 kg butter- What is the total weight of the cake-

Weight of flour = 2/3 kg Weight of sugar = 1/5 kg Weight of butter = 1/6 kg Total weight of cake nbsp;= nbsp;2/3 + 1/5 + 1/6 = (2 × 10) + (1 × 6) + (1 × ...

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Byju's Answer

Standard VI

Mathematics

Addition of Unlike Fractions

A cake contai...

Question

A cake contains $\frac{1}{5}$ kg sugar, $\frac{2}{3}$ kg flour and $\frac{1}{6}$ kg butter. What is the total weight of the cake?

1 \frac{1}{30}

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1 \frac{1}{10}

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1 \frac{1}{15}

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1 \frac{1}{20}

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Solution

The correct option is A $1 \frac{1}{30}$ kg
Weight of flour = $\frac{2}{3}$ kg
Weight of sugar = $\frac{1}{5}$ kg
Weight of butter = $\frac{1}{6}$ kg

Total weight of cake

$= \frac{2}{3} + \frac{1}{5} + \frac{1}{6}$
$= \frac{(2 \times 10) + (1 \times 6) + (1 \times 5)}{30}$
$= \frac{20 + 6 + 5}{30}$
$= \frac{31}{30}$

$1 \frac{1}{30} k g$

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A cake contains 15 kg sugar, 23 kg flour and 16 kg butter. What is the total weight of the cake?

The correct option is A 1130 kgWeight of flour = 23 kg Weight of sugar = 15 kg Weight of butter = 16 kg Total weight of cake =23+15+16 =(2×10)+(1×6)+(1×5)30 =20+6+530 =3130 1130 kg

A cake contains $\frac{1}{5}$ kg sugar, $\frac{2}{3}$ kg flour and $\frac{1}{6}$ kg butter. What is the total weight of the cake?