A car of mass $1000\text{kg}$ moves in a circular path with a constant speed of $12\text{m/s}$. It is turned by ${180}^{\circ }$, while travelling a distance of $628\text{m}$ on the road. The centripetal force acting on the car is

The correct option is C $720\text{N}$
Given, mass of car $\left(m\right)=1000\text{kg}$
Speed of car $\left(v\right)=12\text{m/s}$
To find centripetal force:
$F_c=\frac{m{v}^2}{r}$

We need to find ${}^{\prime }{r}^{\prime }$

To find $r:$ Given that car has turned ${180}^{\circ }$ after travelling $628\text{m}$, distance covered for half circle is,

$\Rightarrow \pi r=628\Rightarrow r=200\text{m}$ $(\pi =3.14)$

Hence the centripetal force will be,
$F_c=\frac{1000\times (12{)}^2}{200}=720\text{N}$

Option C is the correct answer