A cardboard box is 1.2 m long, 72 cm wide and 54 cm high. How many bars of soap can be put into it if each bar measures 6 cm × 4.5 cm × 4 cm?

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Solution

Volume of the cardboard box $= (120 \times 72 \times 54) = 466560 c m^{3}$

Volume of each bar of soap $= (6 \times 4.5 \times 4) = 108 c m^{3}$

Total number of bars of soap that can be accommodated in that box $= \frac{Volume of the box}{Volume of each soap} = \frac{466560}{108} = 4320$ bars

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A cardboard box is 1.2 m long, 72 cm wide and 54 cm high. How many bars of soap can be put into it if each bar measures 6 cm × 4.5 cm × 4 cm?

Volume of the cardboard box =(120×72×54)=466560 cm3 Volume of each bar of soap=(6×4.5×4)=108 cm3 Total number of bars of soap that can be accommodated in that box=Volume of the boxVolume of each soap=466560108=4320 bars

Volume of the cardboard box $= (120 \times 72 \times 54) = 466560 c m^{3}$

Volume of each bar of soap $= (6 \times 4.5 \times 4) = 108 c m^{3}$

Total number of bars of soap that can be accommodated in that box $= \frac{Volume of the box}{Volume of each soap} = \frac{466560}{108} = 4320$ bars