A compound contain 25% hydrogen and 75% carbon by mass. The empirical formula of the compound is:

C H_{4}

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C_{2} H_{2}

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C_{2} H_{6}

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C_{2} H_{4}

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Solution

The correct option is A $C H_{4}$
$\begin{matrix} Element & Atomic mass & % & Relative no. of atoms H & 1 & 25 & 25 & \frac{25}{6.25} = 4 C & 12 & 75 & \frac{75}{12} = 6.25 & \frac{6.25}{6.25} = 1 \end{matrix}$
So, the empirical formula is $C H_{4}$ .

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