A concave mirror of focal length f produces an image n times the size of object. If image is real, then distance of object from mirror, is

\frac{(n - 1)}{f}

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\frac{(n - 1)}{n}

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\frac{(n + 1)}{n}

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(n + 1)f

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Solution

The correct option is B $\frac{(n - 1)}{n}$ f
Since Image is Real
Hence $M = + v e \Rightarrow M = n$
$M = \frac{- v}{u} = n$
$v = - u n$
Using Mirror Formula
$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$
$\frac{1}{- (u n)} + \frac{1}{u} = \frac{1}{f}$
$\frac{1 + n}{u n} = \frac{1}{f}$
$u n = (n + 1) f$
$u = \frac{(n + 1)}{n} f$

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