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Question

A convex lens is put 10cm from a light source and it makes a sharp image on a screen, kept 10cm from the lens. Now a glass block (refractive index 1.5) of 1.5cm thickness is placed in contact with the light source. To get the sharp image again, the screen is shifted by a distance d. Then d is :

A
0.55cm away from the lens
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B
1.1cm away from the lens
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C
0.55cm towards the lens
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D
0
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Solution

The correct option is C 0.55cm away from the lens

Given, 2f=10cm

f=5cm

Now due to glass plate, shift = t(11μ)=1.5(123)=0.5cm

New u=100.5=9.5cm

1v1u=1f

v=47.54.5

Shift, d = v10=59cm

1142312_1330672_ans_e593bd37e6f443369d724d66895563f7.PNG

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