A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same speed how much high above the ground can the cricketer throw the same ball?

The correct option is A 50 m

Given data,

Horizontal distance $=100m$

Let ball is thrown by him with speed $Um/s$ at an angle $\theta$ with horizontal.

We Know maximum horizontal range at $\theta ={45}^0.$

And maximum Range $=\frac{u^2}{g}$

$100=\frac{u^2}{g}$

$u^2=1000m$

when the ball is thrown upward then maximum height attain by the ball $=\frac{u^2}{2g}$

Now, maximum height $=\frac{u^2}{2g}$

$=\frac{1000}{2\times 10}$

$=50m$