A cuboidal vessel is $12\text{cm}$ long and $8\text{cm}$ wide. How high should it be made so that it may hold $480$ cubic centimetre of a liquid?

Given length vessel, $L=12\text{cm}$

Width of vessel, $B=8\text{cm}$

Let, height of the vessel be ${}^{\prime }{H}^{\prime }$.

Given, volume $V=480{\text{cm}}^3$

Volume of cuboid $=LBH$

$LBH=480{\text{cm}}^3$

$h=\frac{480}{12\times 8}\text{cm}=5\text{cm}$

Hence, the vessel should be $5\text{cm}$ high.