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Question

A particle is placed at the point A of a frictionless track ABC as shown in figure. It is pushed slightly towards right. Its speed when it reaches the point B is (g=10ms2)
1364879_b3883fb80d83470b9a68200e895640a3.png

A
10 m/s
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B
10m/s
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C
20ms1
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D
20ms1
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Solution

The correct option is B 10m/s
Potential energy of A is mgh=m×10×1=10m
Kinetic energy at A=0
Mechanical energy at A=10m+0=10m
Potential energy of B=mgh=m×10×5=5m
Kinetic energy at B is 10m5m=5m
Hence Velocity (for speed)
12mv2=5m
12v2=5
v2=5×2
v=10


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