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Question
A particle is projected with a velocity u, at an angle α with the horizontal. Time at which its vertical component of velocity becomes half of its net speed at the highest point will be
A particle is projected with a velocity u, at an angle α with the horizontal. Time at which its vertical component of velocity becomes half of its net speed at the highest point will be
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Solution
The correct option is D u2g(2 sin α−cos α)
Half of speed at highest point =u cos α2 ∴ u cos α2=u sin α−gt
t=u2g(2 sin α−cos α)
∴ (d)
Half of speed at highest point =u cos α2 ∴ u cos α2=u sin α−gt
t=u2g(2 sin α−cos α)
∴ (d)
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