A particle of mass 1 $kg$ slides down a frictionless track (AOC) starting from rest at a point A (height 2 $m$). After reaching C, the particle continues to move freely in air as a projectile. When it reaches its highest point P(height 1 $m$) the kinetic energy of the particle (in $J$) is:(Figure drawn is schematic and not to scale; take $g=10m/s^2$)

Q. A particle of mass 1 $kg$ slides down a frictionless track (AOC) starting from rest at a point A (height 2 $m$). After reaching C, the particle continues to move freely in air as a projectile. When it reaches its highest point P(height 1 $m$) the kinetic energy of the particle (in $J$) is:(Figure drawn is schematic and not to scale; take $g=10m/s^2$)

Q. A particle $(m=1kg)$slides down a frictionless track $\left(AOC\right)$starting from rest at a point $A$ (height $2m$).After reaching $C$, the particle continues to move freely in air as a projectile. When it reaching its highest point $P$ (height $1m$) ,the kinetic energy of the particle (in $J$) is Figure drawn is schematic and not to scale; take $g=10m/s^2$

Q. A particle slides down a frictionless parabolic $(y=x^2)$ track $(A-B-C)$ starting from rest at point $A$ (Figure). Point $B$ is at the vertex of parabola
and point $C$ is at a height less than that of point $A$. After $C$, the particle moves freely in air as a projectile. If the particle reaches highest point at $P$, then is the below statement true or false?



(i) $KE$ at $P=KE$ at $B$

(ii) Height at $P$=height at $A$

(iii) Total energy at $P$ = total energy at $A$

(iv) Time of travel from $A\text{to}B$ = time of travel from (B~\text{to}~P\).

Q. A particle slides down a frictionless parabolic
($y=x^2$) track (A – B – C) starting from rest at
point A (Fig.). Point B is at the vertex of
parabola and point C is at a height less than
that of point A. After C, the particle moves freely
in air as a projectile. If the particle reaches
highest point at P, then

Q. A particle of mass $20\text{gm}$) slides along the frictionless surface. When the particle reaches point $B$, its angular momentum (in ${\text{kg m}}^2/\text{s}$) about $O$ will be


[Take $g=10{\text{m/s}}^2$]