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Question

A ray of light is incident on one face of a transparent slab of thickness 15 cm. The angle of incidence is 60. If the lateral displacement of the ray on emerging from the parallel plane is 53 cm, the refractive index of the material of the slab is

A
1.414
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B
1.532
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C
1.732
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D
None
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Solution

The correct option is C 1.732
i=60
Displacement =tsecrsin(ir)=53
Apply sin(ir)=sinicosrcosisinr
=15secr[32cosrsinr2]=53
32tanr2=13
r=30
Now μsinr=sini
μ=sinisinr=32×21=3=1.732

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