A solid sphere of mass $3kg$ is kept on a horizontal surface. The coefficient of static friction between the surfaces in contact is $2/7$. What maximum force can be applied at the highest point in the horizontal direction so that the sphere does not slip on the surface? (in $N$).

Q. A solid sphere of mass 0⋅50 kg is kept on a horizontal surface. The coefficient of static friction between the surfaces in contact is 2/7. What maximum force can be applied at the highest point in the horizontal direction so that the sphere does not slip on the surface?

Q. A solid sphere of mass 0.50$kg$ is kept on a horizontal surface. The coefficient of static friction between the surfaces in contact is 2$/7$ . What maximum force can be applied at the highest point in the horizontal direction so that the sphere does not slip on the surface?

Q. A solid sphere of mass 0. 50 Kg is krpt on a horizontal surface .The coefficient of static friction between the surfaces in contact is 2 / 7 .The maximum force that can be applied at the highest point in the horizontal direction so that the sphere does not slip on the surface is

Q. A solid sphere of mass $0.50\text{kg}$ is kept at rest on horizontal surface. The coefficient of static friction between the solid sphere and the surface in contact is $\frac{2}{7}$. The maximum force that can be applied at the highest point of sphere in the horizontal direction so that the sphere dosen't slip on the surface is given by $\frac{x}{3}\text{N}$, then value of $x$ is
(Assume $g=10{\text{ms}}^{-2}$)

Q. A solid sphere of mass $0.50\text{kg}$ is kept at rest on horizontal surface. The coefficient of static friction between the solid sphere and the surface in contact is $\frac{2}{7}$. The maximum force that can be applied at the highest point of sphere in the horizontal direction so that the sphere dosen't slip on the surface is given by $\frac{x}{3}\text{N}$, then value of $x$ is
(Assume $g=10{\text{ms}}^{-2}$)