A solution of glucose $\left({\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_6\right)$ in water is labelled as 10% by weight. What would be the molality of the solution?
(Molar mass of glucose = 180 g mol${}^{-1}$)

The correct option is A 0.6

Molality of a solution is defined as the number of moles of solute dissolved per kg of solvent.

$C_6{H}_{12}{O}_6$=10% by weight.

Thus in 100 g solution mass of glucose = 10 g and of water =90 g

$Numberofmolesofglucose=\frac{mass}{molarmass}$

$n=\frac{10}{180}=\frac{1}{18}mol$

Mass of solvent = 90 g= 0.09 kg

Molality, $m=\frac{\left(\frac{1}{18}\right)}{0.09}$

$m=\frac{100}{18\times 9}=0.617molal\approx 0.6molal$

The molality of a solution of glucose ($C_6{H}_{12}{O}_6$) in water is labelled as 10% by weight is 0.617 molal.

Hence, the correct option is $\left(B\right)$