A source of sound of frequency 450 cycles/sec is moving towards a stationary observer with 34 m/sec speed. If the speed of sound is 340 m/sec, then the apparent frequency will be

410 cycles/sec

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500 cycles/sec

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550 cycles/sec

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450 cycles/sec

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Solution

The correct option is B
500 cycles/sec

n' = n $(\frac{v}{v - v_{s}}) = 450 (\frac{340}{340 - 34}) = 500$ cycles/sec

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A source of sound of frequency 450 cycles/sec is moving towards a stationary observer with 34 m/sec speed. If the speed of sound is 340 m/sec, then the apparent frequency will be

The correct option is B 500 cycles/sec n' = n (vv−vs)=450(340340−34)=500 cycles/sec

The correct option is B
500 cycles/sec

n' = n $(\frac{v}{v - v_{s}}) = 450 (\frac{340}{340 - 34}) = 500$ cycles/sec