1
Question
A sphere of radius 1cm has potential of 8000V , then energy density near it's surface will be
a) 6400000J/m3
b) 8000J/m3
c) 32J/m3
d) 2.83J/m3
a) 6400000J/m3
b) 8000J/m3
c) 32J/m3
d) 2.83J/m3
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Solution
Energy density = (1/2)∈0E2
= (1/2) × 8.86 × 10–12(v/r)2
= 4.43 × 10–12 × [(8000) / (10–2)]2
= 283.5 × 10–2
= 2.83 J/m3
Energy density = (1/2)∈0E2
= (1/2) × 8.86 × 10–12(v/r)2
= 4.43 × 10–12 × [(8000) / (10–2)]2
= 283.5 × 10–2
= 2.83 J/m3
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