A stone is dropped from a height of 20 m. Calculate the velocity with which it hits the ground and the time taken. ( $g = 10 m / s^{2}$ )

15 m/s, 1.5 sec

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20 m/s, 2 sec

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35 m/s, 0.4 sec

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10 m / s^{2}

, 0.2 sec

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Solution

The correct option is B 20 m/s, 2 sec
Distance (s) $= 20 m$
Initial velocity $= 0 m / s$
$g = 10 m / s^{2}$

By using the formula:
$v^{2} = u^{2} + 2 a s$
$v^{2} = 0^{2} + 2 \times 10 \times 20$
$v^{2} = 400$
$v^{2} = \sqrt{400}$
$v = 20 m / s$

For calculating time:
$V = u + a t$
$20 = 0 + 10 \times t$
$t = \frac{20}{10}$
$t = 2 s e c$
The the stone will hit the ground with a velocity of $20 m / s$ in sec.

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