A stone is dropped from the top of a tall building. A second stone is thrown down from same point 2 seconds later, with an initial speed of 30 m/s. If both stones hit the ground at same instant, find the height of building. ( g = 10 m/s2)
A
80 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
60 m
No worries! Weāve got your back. Try BYJUāS free classes today!
C
120 m
No worries! Weāve got your back. Try BYJUāS free classes today!
D
160 m
No worries! Weāve got your back. Try BYJUāS free classes today!
Open in App
Solution
The correct option is A 80 m āh=ā12gt2 (for 1st stone) h=5t2---(1) āh=āu(tā2)ā12g(tā2)2 (for 2nd stone) h=30(tā2)+5(tā2)2 ---- (2) Equating (1) and (2), 5t2=30tā60+5t2ā20t+20 ā10tā40=0t=4 h=5t2=5Ć16=80m