A stone is thrown up with a speed of 10 m/s. How high will it go before it begins to fall? ( $g = 9.8 m / s^{2}$ )

51 m

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0.51 m

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510 m

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5.1 m

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Solution

The correct option is C 5.1 m
For this problem we have to use the formula : $v^{2} - u^{2} = 2 a S$
Here, $v = 0$ , at highest point the $v e l o c i t y$ of stone is $z e r o$ and
$a = g = 9.8, u = 10 m / s$ and $S = h$
Thus, $0^{2} - 10^{2} = 2 (9.8) h$ or $h = 5.1 m$

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