A thin prism P1 with angle 4⁰ and made from a glass of refractive index 1.54 is combined with another prism P2 made from glass of refractive index 1.72 to produce dispersion withiutdeviation . The angle of prism P2 is:-
5.33⁰/4⁰/3⁰/1.6⁰

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Solution

$F o r a p r i s m t h e a n g l e o f d e v i a t i o n δ c a n b e w r i t t e n a s δ = (μ - 1) A w h e r e μ = r e f r a c t i v e i n d e x a n d A = a n g l e o f p r i s m n o w f o r n o d e v i a t i o n f r o m a c o m p o s i t e p r i s m a s s e m b l y t h e d e v i a t i o n c a u s e d b y o n e s h o u l d b e o p p o s i t e t o t h e o t h e r . S o w e c a n w r i t e (μ_{2} - 1) A_{2} = - (μ_{1} - 1) A_{1} |A_{2}| = \frac{(μ_{1} - 1)}{(μ_{2} - 1)} A_{1} = \frac{1.54 - 1}{1.72 - 1} \times 4 = 3 (A N S)$

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P_{1}

4^{\circ}

1.54

P_{2}

1.72

P_{2}

P_{1}

4^{\circ}

P_{2}

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