A travelling wave $Y = A$ sin $(k x - ω t + θ)$ passes from a heavier string to lighter string. The reflected has amplitude $0.5$ $A$ . The junction of the string is $x = 0$ . The equation of the reflected wave is:

y^{'} = 0.5 A sin (k x + ω t + θ)

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y^{'} = - 0.5 A sin (k x + ω t + θ)

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y^{'} = - 0.5 A sin (ω t - k x - θ)

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y^{'} = - 0.5 A sin (k x + ω t - θ)

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Solution

The correct option is D $y^{'} = - 0.5 A sin (k x + ω t + θ)$
$\begin{matrix} Y = A sin (K x - ω t + θ) y^{'} = 0.5 A sin (K x + ω t + θ + π) = - 0.5 A sin (K x + ω t + θ) H e n c e, o p t i o n B i s c o r r e c t a n s w e r . \end{matrix}$

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A travelling wave Y=A sin (kx−ωt+θ) passes from a heavier string to lighter string. The reflected has amplitude 0.5 A. The junction of the string is x=0. The equation of the reflected wave is:

The correct option is D y′=−0.5Asin(kx+ωt+θ)Y=Asin(Kx−ωt+θ)y′=0.5Asin(Kx+ωt+θ+π)=−0.5Asin(Kx+ωt+θ)Hence,optionBiscorrectanswer.

A travelling wave $Y = A$ sin $(k x - ω t + θ)$ passes from a heavier string to lighter string. The reflected has amplitude $0.5$ $A$ . The junction of the string is $x = 0$ . The equation of the reflected wave is:

The correct option is D $y^{'} = - 0.5 A sin (k x + ω t + θ)$
$\begin{matrix} Y = A sin (K x - ω t + θ) y^{'} = 0.5 A sin (K x + ω t + θ + π) = - 0.5 A sin (K x + ω t + θ) H e n c e, o p t i o n B i s c o r r e c t a n s w e r . \end{matrix}$