A water pond appears to be 2-5 m deep- If the refractive index of water is 4-3- Determine the actual depth of the pond-

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Refraction through a Rectangular Glass Slab

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Question

A water pond appears to be $2.5 m$ deep. If the refractive index of water is $\frac{4}{3}$ . Determine the actual depth of the pond.

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Solution

Step 1: Given data.
Refractive index is $(\frac{4}{3})$
Apparent depth is $2.5 m$ .
Step 2: Find the actual or real depth.
We know that,
$Refractive index = \frac{Real Depth}{Apparent Depth}$
Putting the value in the equation,
$\frac{4}{3} = \frac{real depth}{2.5 m}$
$\begin{array}{rcl} real depth & = & \frac{2.5 \times 4}{3} \\ = & 3.33 m \end{array}$
Thus, the actual depth of the pond is $3.33 m$ .

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A water pond appears to be 2.5m deep. If the refractive index of water is 43. Determine the actual depth of the pond.

Step 1: Given data.Refractive index is 43Apparent depth is 2.5m.Step 2: Find the actual or real depth.We know that,Refractiveindex=RealDepthApparentDepthPutting the value in the equation,43=realdepth2.5mrealdepth=2.5×43=3.33mThus, the actual depth of the pond is 3.33m.

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