A water pond appears to be $2.7$ in deep. If the refractive index of water is $4 / 3$ , find the actual depth of the pond.

2.7 m

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0.9 m

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3.6 m

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1.8 m

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Solution

The correct option is C $3.6 m$
$R I = \frac{real depth}{apparent depth}$

Substituting, $\frac{4}{3} = \frac{r e a l d e p t h}{2.7}$

Therefore, $r e a l d e p t h = \frac{2.7 \times 4}{3} = 3.6$

$R e a l d e p t h = 3.6 m$

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A water pond appears to be 2.7 in deep. If the refractive index of water is 4/3, find the actual depth of the pond.

The correct option is C 3.6 mRI=real depthapparent depthSubstituting, 43=real depth2.7Therefore, real depth=2.7×43=3.6Real depth=3.6m

A water pond appears to be $2.7$ in deep. If the refractive index of water is $4 / 3$ , find the actual depth of the pond.

The correct option is C $3.6 m$
$R I = \frac{real depth}{apparent depth}$

Substituting, $\frac{4}{3} = \frac{r e a l d e p t h}{2.7}$

Therefore, $r e a l d e p t h = \frac{2.7 \times 4}{3} = 3.6$

$R e a l d e p t h = 3.6 m$