ABCD represents a glass slab and PQRS indicates the path of a light ray passing through the slab. If the refractive index of the glass is √3, find the lateral displacement (x).
A
15 cm
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B
16.33 cm
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C
8.66 cm
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D
12.33 cm
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Solution
The correct option is C8.66 cm Lateral shift due to a glass slab is given by δ=tcosrsin(i−r) here t is the thickness of the slab. and it is given t=15cmr=300 From Snell's Law μ=sinisinr √3=sinisin300 sini=√32=sin600 i=600 So, δ=15cos300sin(600−300) =15√32/12 δ=8.66cm