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Question

ABCD represents a glass slab and PQRS indicates the path of a light ray passing through the slab. If the refractive index of the glass is 3, find the lateral displacement (x).
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A
15 cm
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B
16.33 cm
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C
8.66 cm
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D
12.33 cm
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Solution

The correct option is C 8.66 cm
Lateral shift due to a glass slab is given by δ=tcosrsin(ir) here t is the thickness of the slab.
and it is given t=15cmr=300
From Snell's Law
μ=sinisinr
3=sinisin300
sini=32=sin600
i=600
So, δ=15cos300sin(600300)
=1532/12
δ=8.66cm

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