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Question

A pendulum has time period T in air. When it is made to oscillate in water, it acquired a time period T=2T. The specific gravity of the pendulum bob is equal to

A
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B
2
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C
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D
None of these
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Solution

The correct option is B 2
The effective acceleration of a bob in water =g=g(1dD) where d & D are the density of water & the bob respectively.
Dd = specific gravity of the bob.
Since the period of oscillation of the bob in air & water are given as
T=2πlg&T=2πlgTT=gg=1dD=11D
Putting TT=12, we obtain
12=11D
1D=12
D=2

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