An alkali metal $A$ gives a compound $B$ (molecular mass $= 40$ ) on reacting with water. The compound $B$ gives a soluble compound $C$ on treatment with aluminium oxide. Metal $A$ is:

A l

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K

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N a

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M g

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Solution

The correct option is B $N a$
Alkali metal $(A)$ is sodium ( $N a$ ) which forms $N a O H$ (compound $B$ ) with water .The reaction can be written as:
$2 N a + 2 H_{2} O \to 2 N a O H + H_{2}$
$N a O H$ reacts with aluminium oxide( $A l_{2} O_{3}$ ) to form sodium aluminate (compound $C$ ) with chemical formula $N a A l O_{2}$ .The reaction can be written as:
$A l_{2} O_{3} + 2 N a O H \to 2 N a A l O_{2} + H_{2} O$

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An alkali metal A gives a compound B (molecular mass =40) on reacting with water. The compound B gives a soluble compound C on treatment with aluminium oxide. Metal A is:

An alkali metal $A$ gives a compound $B$ (molecular mass $= 40$ ) on reacting with water. The compound $B$ gives a soluble compound $C$ on treatment with aluminium oxide. Metal $A$ is: