wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An elevator ascends with an upward acceleration of 2 ms2 . At the instant its upward speed is 2.5 ms1, a loose bolt is dropped from the ceiling of the elevator 3m from the floor. (g=10ms2 ). The time of flight of the bolt from the ceiling to floor approximately is


A
1s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.1s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.7s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1.3s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 0.7s
Velocity of bolt relative to elevator = 2.5 - 2.5 = 0
Acceleration of bolt relative to elevator a = 10 - (-2) = 12 ms1
Using the relation, s=ut+12at2, we have 3.0=0×t+12×12t2t=12s=0.7s

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon