An object is placed at a distance of 10 cm from a convex mirror of focal length 5cm.
Calculate the distance of an image from mirror.

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Solution

Given,
Object distance = $u = - 10 c m$
Focal length of the convex mirror = $f = 5 c m$
To find: Image distance $v = ?$
Using mirror formula, $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$ , we get
$\frac{1}{5} = \frac{1}{v} + \frac{1}{- 10}$
$\Rightarrow \frac{1}{v} = \frac{1}{5} + \frac{1}{10} = \frac{2 + 1}{10} = \frac{3}{10}$
$\Rightarrow v = \frac{10}{3} c m = 3.33 c m$ .
So the image is virtual, erect, diminished and formed behind the mirror at a distance of 3.33 cm.

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An object is placed at a distance of 10 cm from a convex mirror of focal length 5cm.Calculate the distance of an image from mirror.

Given,Object distance = u=−10cm Focal length of the convex mirror = f=5cmTo find: Image distance v=?Using mirror formula, 1f=1v+1u, we get15=1v+1−10⇒1v=15+110=2+110=310⇒v=103cm=3.33cm.So the image is virtual, erect, diminished and formed behind the mirror at a distance of 3.33 cm.

An object is placed at a distance of 10 cm from a convex mirror of focal length 5cm.
Calculate the distance of an image from mirror.