An object of size $7.5 cm$ is placed in front of a convex mirror of radius of curvature $25 cm$ at a distance of $40 cm$ . The size of the image should be -

0.8 cm

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1.78 cm

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1 cm

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2.3 cm

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Solution

The correct option is B $1.78 cm$
Given: $u = 40 cm, R = 25 cm, O = + 7.5$

BY the magnification,
$\frac{I}{O} = \frac{f}{f - u}$
$\Rightarrow \frac{I}{+ 7.5} = \frac{\frac{25}{2}}{\frac{25}{2} - (- 40)}$
$\Rightarrow I = 1.78 cm$

Hence, option $(B)$ is correct.

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