An ore on treatment with dilute hydrochloric acid gives back effervescence. From the following list, what type of ore is this?
[sulfide, carbonate, phosphate, nitrate]

Open in App

Solution

Carbonates on treatment with dilute $H C l$ produces back effervescence. The method of calcination is used for this purpose.
The series of reaction involved can be given as:

(i) $Z n C O_{3} ⟶ Z n O + C O_{2}$
(ii) $Z n O + C ⟶ Z n + C O$

So, the correct answer is carbonate.

Suggest Corrections

Similar questions

Q. And ore on treatment with dilute hydrochloric acid produces brisk effervescence. What type of ore is this? Write the steps required to obtain metal from then restore

Q. An ore gives carbon dioxide on treatment with dilute acid . What steps will you take to convert such a ore in to free metal?

An ore on treatment with dilute HCL gives a smell like that of rotten eggs. What type of ore is it? Give equations and explain the operation required to obtain metal from its ore.

Q. Which of the following salts does not liberate carbon-dioxide on treatment with dilute hydrochloric acid?

Q. Addition of silver nitrate to hydrochloric acid, gives an insoluble precipitate of the respective chloride, This precipitate is soluble in ammonium hydroxide and insoluble in dilute nitric acid.

Join BYJU'S Learning Program

An ore on treatment with dilute hydrochloric acid gives back effervescence. From the following list, what type of ore is this?[sulfide, carbonate, phosphate, nitrate]

Carbonates on treatment with dilute HCl produces back effervescence. The method of calcination is used for this purpose.The series of reaction involved can be given as:(i) ZnCO3⟶ZnO+CO2(ii) ZnO+C⟶Zn+COSo, the correct answer is carbonate.

An ore on treatment with dilute hydrochloric acid gives back effervescence. From the following list, what type of ore is this?
[sulfide, carbonate, phosphate, nitrate]

Carbonates on treatment with dilute $H C l$ produces back effervescence. The method of calcination is used for this purpose.
The series of reaction involved can be given as:

(i) $Z n C O_{3} ⟶ Z n O + C O_{2}$
(ii) $Z n O + C ⟶ Z n + C O$

So, the correct answer is carbonate.