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Laws of Exponents

Application o...

Question

Application of laws of exponents based on fractional and algebraic powers
Solve for $x$ :
$2^{2 x + 1} = 8$

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Solution

Given that:
$2^{2 x + 1} = 8$
$∵ 8 = 2^{3}$
Since we know that if base is same in both left and right side of equality than powers are equal.
So,
$2^{2 x + 1} = 2^{3}$
$2 x + 1 = 3$
$2 x = 2$
$x = 1$
Answer.

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