Assertion: $N_{2}$ and $N O^{+}$ are diamagnetic substances.
Reason: $N O^{+}$ is isoelectronic with $N_{2} .$

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Solution

Due to the absence of unpaired electron in $N O^{+}$ and $N_{2}$ , both are diamagnetic in nature.
Total np. of $e^{-}$ in $N O^{+} = 7 + 8 - 1 = 14$
Total no. of $e^{-}$ in $N_{2} = 7 + 7 = 14$
Therefore. both are isoelectronic.

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