At a particular temperature, the ratio of equivalent conductance to specific conductance of a $0.01 N$ NaCl solution is :

10^{5} c m^{3}

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10^{3} c m^{3}

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10 c m^{3}

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10^{5} c m^{2}

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Solution

The correct option is B $10^{5} c m^{3}$
At a particular temperature, the ratio of equivalent conductance to specific conductance of a 0.01 N NaCl solution is $10^{5} c m^{3}$
$Λ_{e q} = \frac{1000 κ}{N}$
$\frac{Λ_{e q}}{κ} = \frac{1000}{0.01} = 10^{5} c m^{3} . e q^{- 1}$

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