At standard pressure and temperature conditions the density of a gas in $g$ and whose molecular weight is $45$ , then volume occupied by gas in $1$ is:

2

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22.4

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11.2

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1000

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Solution

The correct option is A $2$
Density $= \frac{m a s s}{V o l u m e}$
One mole of any gas would occupy 22.4L at STP.
The gas in question would have molar mass of $45 g / m o l$
$∴$ Density $= \frac{m}{V} = \frac{45 g}{22.4 L} = 2.0 g / L$

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